NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2
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Board CBSE
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TextBook NCERT
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CLASS Class 8
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SUBJECT Maths
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CHAPTER Chapter 9
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SUBJECT Algebraic Expressions and Identities
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Visit NCERT SOLUTIONS
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Class 8 Maths Algebraic Expressions and Identities Exercise 9.1
Class 8 Maths Algebraic Expressions and Identities Exercise 9.2
Class 8 Maths Algebraic Expressions and Identities Exercise 9.3
Class 8 Maths Algebraic Expressions and Identities Exercise 9.4
Class 8 Maths Algebraic Expressions and Identities Exercise 9.5
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NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2 with Answers
Exercise: 9.2
Question 1.
Find the product of the following pairs of monomials:
(i) 4, 7p
(ii) – 4p, 7p
(iii) – 4p, 7pq
(iv) 4p³,−3p
(v) 4p, 0.
Solution.
Question 2.
Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively:
(i) (p, q);
(ii) (10m, 5n);
(iii) (20x²,5y²);
(iv) (4x,3x²);
(v) (3mn, 4np).
Solution:
(i)
Let, Length of the rectangle = p
Breadth of the rectangle = q
∴ Area of the rectangle
= Length x Breadth
= pxq
= pq Square units
(ii)
Let, Length of the rectangle = 10 m
Breadth of the rectangle = 5 n
∴ Area of the rectangle
= Length x Breadth
= (10m) x (5n)
= 50 mn Square units
(iii)
Let Length of the rectangle = 20x²
Breadth of the rectangle = 5y²
∴ Area of the rectangle
= Length x Breadth
= (20x²) x (5y²)
= 100x²y² Square units
(iv)
Let, Length of the rectangle = 4x
Breadth of the rectangle = 3x²
∴ Area of the rectangle
= Length x Breadth =
(4x) x (3x²)
= 12x³ Square units
(v)
Let, Length of the rectangle = 3 mn
Breadth of the rectangle = 4np
∴ Area of the rectangle
= Length x Breadth
= (3mn) x (4np)
= 12mn²p Square units
Question 3.
Complete the table of products.
Question 4.
Obtain the volume of rectangular boxes with the following length, breadth and height respectively:
(i) 5a,3a²,7a⁴
(ii) 2p, 4q, 8r
(iii) xy,2x²y,2xy²
(iv) a, 2b, 3c
Solution:
(i) Volume of rectangular box = length x breadth x height
= 5a×3a²×7a⁴
= (5×3×7) ×(a×a²×a⁴)
= 105a7 cubic units
(ii) Volume of rectangular box = length x breadth x height
= 2p×4q× 8r
=(2×4×8) ×(p×q×r)
=64pqr cubic units
(iii) Volume of rectangular box = length x breadth x height
= xy×2x²y×2xy²
= 4x⁴y⁴ cubic units
(iv) Volume of rectangular box = length x breadth x height
= a×2b×3c
= 6abc cubic units
Question 5.
Obtain the product of
(i) xy, yz, zx
(ii) a,−a²,a³
(iii) 2,4y,8y²,16y³
(iv) a, 2b, 3c, 6abc
(v) m, – mn, mnp.
Solution:
(i) xy, yz, zx
Required product
= (xy) x (yz) x (zx)
= x²y²z²
(ii) a,−a²,a³
Required product = (a) × (−a²)× (a³)
= -a6
(iii) 2,4y,8y²,16y³
Required product =( 2)×(4y)×(8y²)×(16y³)
= 1024y6
(iv) a, 2b, 3c, 6abc
Required product =(a) × (2b) ×(3c) × (6abc)
= 36a²b²c²
(v) m, – mn, mnp
Required product =(m) ×(– mn)×(mnp)
= - m³n²p
NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2 with Answers
