NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2
Whole Numbers: Here you get NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2 with Answers Pdf free download.In NCERT Solution Class 6 Maths with Answers you get question-answer based on latest exam pattern. By providing NCERT Chapter-wise Class 6 Maths Questions with Answers our target to help students get concept of the lesson very well.
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Board CBSE
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TextBook NCERT
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CLASS Class 6
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SUBJECT Maths
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CHAPTER Chapter 2
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SUBJECT Whole Numbers
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NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2 with Answers
Exercise 2.2
Question 1:
Find the sum by suitable rearrangement:
(a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 647
Answer 1:
(a) 837 + 208 + 363
= (837 + 363) + 208
= 1200 + 208
= 1408
(b) 1962 + 453 + 1538 + 647
= (1962 + 1538) + (453 + 647)
= 3500 + 1100
= 4600
Question 2:
Find the product by suitable arrangement:
(a) 2 x 1768 x 50 (b) 4 x 166 x 25
(c) 8 x 291 x 125 (d) 625 x 279 x 16
(e) 285 x 5 x 60 (f) 125 x 40 x 8 x 25
Answer 2:
(a) 2 x 1768 x 50
= (2 x 50) x 1768
= 100 x 1768
= 176800
(b) 4 x 166 x 25
= (4 x 25) x 166
= 100 x 166
= 16600
(c) 8 x 291 x 125
= (8 x 125) x 291
= 1000 x 291
= 291000
(b) 625 x 279 x 16
= (625 x 16) x 279
= 10000 x 279
= 2790000
(e) 285 x 5 x 60
= 284 x (5 x 60)
= 284 x 300
= 85500
(f) 125 x 40 x 8 x 25
= (125 x 8) x (40 x 25)
= 1000 x 1000
= 1000000
Question 3:
Find the value of the following:
(a) 297 x 17 + 297 x 3
(b) 54279 x 92 + 8 x 54279
(c) 81265 x 169 – 81265 x 69
(d) 3845 x 5 x 782 + 769 x 25 x 218
Answer 3:
(a) 297 x 17 + 297 x 3
= 297 x (17 + 3)
= 297 x 20
= 5940
(b) 54279 x 92 + 8 x 542379
= 54279 x (92 + 8)
= 54279 x 100
= 5427900
(c) 81265 x 169 – 81265 x 69
= 81265 x (169 – 69)
= 81265 x 100
= 8126500
(d) 3845 x 5 x 782 + 769 x 25 x 218
= 3845 x 5 x 782 + 769 x 5 x 5 x 218)
= 3845 x 5 x 782 + 3845 x 5 x 218
= 3845 x 5 x (782 + 218)
= 3845 x 5 x 1000
= 19225000
Question 4:
Find the product using suitable properties:
(a) 738 x 103 (b) 854 x 102
(c) 258 x 1008 (d) 1005 x 168
Answer 4:
(a) 738 x 103
= 738 x (100 + 3)
= 738 x 100+ 2)+ 738 x 3
= 73800+ 2214
= 76014
(b) 854 x 102
= 854 x (100+2)
= 854 x 100 + 854 x 2
= 85400 + 1708
= 87108
(c) 258 x 1008
= 258 x (1000 + 8)
= 258 x 1000 + 258 x 8
= 258000 + 2064
= 260064
(d) 1005 x 168
= (1000 + 5) x 168
= 1000 x 168 + 5 x 168
= 168000 + 840
= 168840
NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2 with Answers
Question 5:
A taxi-driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If petrol costs ₹ 44 per litre, how much did he spend on petrol?
Answer 5:
Petrol filled on Monday = 40 litres
Petrol filled on next day = 50 litres
Total petrol filled =(40+50) = 90 litres
Now,
Cost of 1 litre petrol = ₹ 44
Cost of 90 litres petrol = 44 x 90
= 44 x (100 – 10)
= 44 x 100 – 44 x 10
= 4400 – 440
= ₹ 3960
Hence, he spent ₹ 3960 on petrol.
Question 6:
A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs ₹15 per litre, how much money is due to the vendor per day?
Answer 6:
The vendor supply of milk in morning = 32 litres
The vendor supply of milk in evening = 68 litres
The vendor supply total milk on that day = 32 + 68 = 100 litres
Now, Cost of 1 litre milk = ₹15
Therefore, total cost of 100 litres milk = 15 x 100 = ₹1500
Therefore, ₹1500 is due to the vendor per day.
Question 7:
Match the following:
Answer 7:
NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2 with Answers
