CBSE Factorisation Mathematics Class VIII(8TH)

Factorisation

Factors: When an algebraic equation can be written as the product of two or more expressions then each of these is called a factor of the give equation.

Factorisation: The process of finding two or more expressions whose product is the given expression is called factorisation.

Factorisation is the reverse process of multiplication.

Product	Factorisation
(i) 3x(4X-5Y)=12Xᶻ-15XY	(i) 12xᶻ-15xy=3x(4x-5y)
(ii) (a+3)(a-2)=aᶻ+a-6	(ii) aᶻ+a-6=(a+3)(a-2)

Method to Find Factorisation When a Common Monomial Factor Occurs is Each Case:

Step1: Find the HCF of all terms of the give expression.

Step2: Divide each term of the given expression by this HCF.

Step3: Write the given expression as the product of this HCF  and the quotient obtained is step2.

Factorise:

1(i) 12x+15

    =3(4x+5)

(ii) 14m+21

   =7(2m+3)

(iii) 9n+12nᶻ

    =3n(3+4n)

2(i) 16aᶻ-24ab

  = 8a(2a+3b)

(ii) 15abᶻ-20aᶻb

   = 5ab(3b-4a)

(iii) 12xᶻyᶾ-21xᶾyᶻ

   = 3xᶻyᶻ(4x-7y)

3(i) 24xᶾ-36xᶻy

   = 12xᶻ(x-3y)

(ii) 10xᶾ-15xᶻ

   = 5xᶻ(2x-3)

(iii) 36xᶾy-60xᶻyᶾz

   = 12xᶻy(3x-5yᶻz)

4(i) 9xᶾ-6xᶻ+12x

   = 3x(3xᶻ-2x+4)

(ii) 8xᶻ-72XY+12X

   = 4x(2x-9y+3)

(iii) 18aᶾbᶾ-27aᶻbᶾ+36aᶾbᶻ

   = 9aᶻbᶻ(2ab-3b+4a)

5(i) 14xᶾ+21x⁴y-28xᶻyᶻ

   = 7xᶻ(2x+3xᶻy-4yᶻ)

(ii) -5-10t+20tᶻ

   = 20tᶻ-10t-5

   = 5(4tᶻ-2t-1)

6(i) x(x+3)+5(x+3)

 = (x+3)(x+5)

(ii) 5x(x-4)-7(x-4)

= (x-4)(5x-7)

(7) 6a(a-2b)+5b(a-2b)

=(a-2b)(6a+5b)

(8) xᶾ(2a-b)+xᶻ(2a-b)

=xᶻ(2a-b)(x-1)

(9) 9a(3a-5b)-12aᶻ(3a-5b)

=3a(3a-5b)(3-4a)

(10) (x+5)ᶻ-4(x+5)

=(x+5){(x+5)-4}

= (x+5)(x+5-4)

=(x+5)(x+1)

(11) 3(a-2b)ᶻ-5(a-2b)

=(a-2b){3(a-2b)-5}

=(a-2b)(3a-6b-5)

(12) 2a+6b-3(a+3b)ᶻ

=2(a+3b)-3(a+3b)ᶻ

=(a+3b){2-3(a+3b)}

=(a+3b)(2-3a-9b)

(13) 16(2p-3q)ᶻ-4(2p-3q)

=4(2p-3q){4(2p-3q)-1}

=4(2p-3q)(8p-12q-1)

(14) x(a-3)+4(3-a)

=x(a-3)-4(a-3)

=(a-3)(x-4)

(15) 12(2x-3y)ᶻ-16(3y-2x)

=12(2x-3y)ᶻ+16(2x-3y)

=4(2x-3y){3(2x-3y)+4)

4(2x-3y)(6x-9y+4)

(16) (x+y)(2x+5)-(x+y)(x+3)

=(x+y){(2x+5)-(x+3)}

=(x+y)(2x+5-x-3)

=(x+y)(x+2)

(17) ar+br+at+bt

=ar+at+br+bt

=a(r+t)+b(r+t)

=(r+t)(a+b)

(18) xᶻ-ax-bx+ab

=x(x-a)-b(x-a)

=(x-a)(x-b)

(19)  abᶻ-bcᶻ-ab+cᶻ

=abᶻ-ab-bcᶻ+cᶻ

=ab(b-1)-cᶻ(b-1)

=(b-1)(ab-cᶻ)

(20) xᶻ-xz+xy-yz

=x(x-z)+y(x-z)

=(x-z)(x+y)

(21) 6ab-bᶻ+12ac-2bc

=6ab+12ac-bᶻ-2bc

=6a(b+2c)-b(b+2c)

=(b+2c)(6a-b)

(22) (x-2y)ᶻ+4x-8y

=(x-2y)ᶻ+4(x-2y)

=(x-2y){(x-2y)+4}

=(x-2y)(x-2y+4)

(23) yᶻ-xy(1-x)-xᶾ

=yᶻ-xy+xᶻy-xᶾ

=y(y-x)+xᶻ(y-x)      

=(y-x)(y+xᶻ)              

CBSE Factorisation Mathematics Class VIII(8TH)  


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