NCERT Solution for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.3

 

NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.3 with questions and answers, mcq notes in pdf free to download as worksheet for whole numbers

Playing with Numbers: Here you get NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.3 with Answers Pdf free download.In NCERT Solution Class 6 Maths with Answers you get question-answer based on latest exam pattern. By providing NCERT Chapter-wise Class 6 Maths Questions with Answers our target to help students get concept of the lesson very well.


You can also visit NCERT Questions for Class 6 Maths Chapter-wise Questions with Answers to revise your syllabus thoroughly and enhance the chances of securing high marks in your board exams. It also helps in your CBSE NCERT Class 6 online test, online exam for admission well.

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 Board                    CBSE


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TextBook                NCERT


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CLASS                    Class 6


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SUBJECT                 Maths


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CHAPTER               Chapter 3


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SUBJECT           Playing with Numbers                      


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Visit                   NCERT Solutions

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 NCERT Class 6 Chapter 3 Ex 3.1

 NCERT Class 6 Chapter 3 Ex 3.2

NCERT Class 6 Chapter 3 Ex 3.4

NCERT Class 6 Chapter 3 Ex 3.5

NCERT Class 6 Chapter 3 Ex 3.6

NCERT Class 6 Chapter 3 Ex 3.7


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 NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.3 with Answers


Exercise 3.3

Question 1

Using divisibility test, determine which of the following numbers are divisible by 2; by 3; by 4; by 5; by 6; by 8; by 9; by 10; by 11. (Say yes or no)



Number

Divisibility By

2

3

4

5

6

7

8

9

10

11

128

Yes

No

Yes

No

No

No

Yes

No

No

No

990











1586











275











6686











639210











429714











2856











3060











406839



N









Answer 1:



Number

Divisibility By

2

3

4

5

6

7

8

9

10

11

128

Yes

No

Yes

No

No

No

Yes

No

No

No

990

Yes

Yes

No

Yes

Yes

No

No

Yes

Yes

No

1586

Yes

No

No

No

No

No

No

No

No

No

275

No

No

No

Yes

No

No

No

No

No

Yes

6686

Yes

No

No

No

No

No

No

No

No

No

639210

Yes

Yes

No

Yes

Yes

No

No

No

Yes

Yes

429714

No

Yes

No

No

No

No

No

Yes

No

No

2856

Yes

Yes

Yes

No

Yes

Yes

Yes

No

No

No

3060

Yes

No

Yes

Yes

No

No

No

Yes

Yes

No

406839

No

Yes

No

No

No

No

No

No

No

No





Question 2

Using divisibility test, determine which of the following numbers are divisible by 4; by 8:

(a) 572 (b) 726352 (c) 5500 (d) 6000

(e) 12159 (f) 14560 (g) 21084 (h) 31795072 (i) 1700 (j) 2150

Answer 2: 

(a) 572 

Divisible by 4 because its last two digits are divisible by 4.

Not divisible by 8 because its last three digits are not divisible by 8.


(b) 726352

Divisible by 4 because its last two digits are divisible by 4.

Divisible by 8 because its last three digits are divisible by 8.


(c) 5500

Divisible by 4 because its last two digits are divisible by 4.

Not divisible by 8 because its last three digits are not divisible by 8.


(d) 6000

Divisible by 4 because its last two digits are 0.

Divisible by 8 because its last three digits are 0.


(e) 12159

Not divisible by 4 because its last two digits are not divisible by 4.

Not divisible by 8 because its last three digits are not divisible by 8.


(f) 14560

Divisible by 4 because its last two digits are divisible by 4.

Divisible by 8 because its last three digits are divisible by 8.


(g) 21084

Divisible by 4 because its last two digits are divisible by 4.

Not divisible by 8 because its last three digits are not divisible by 8.


(h) 31795072

Divisible by 4 because its last two digits are divisible by 4.

Divisible by 8 because its last three digits are divisible by 8.


(i) 1700

Divisible by 4 because its last two digits are 0.

Not divisible by 8 because its last three digits are not divisible by 8.


(j) 5500

Not divisible by 4 because its last two digits are not divisible by 4.

Not divisible by 8 because its last three digits are not divisible by 8.



NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.3 with Answers

Question 3

Using divisibility test, determine which of the following numbers are divisible by 6:

(a) 297144 (b) 1258 (c) 4335 (d) 61233

(e) 901352 (f) 438750 (g) 1790184 (h) 12583(i) 639210 (j) 17852


Answer 3

(a) 297144

Divisible by 2 because its units place is an even number and also divisible by 3 because the sum of its digits (= 27) is divisible by 3.

Since the number is divisible by both 2 and 3, therefore, it is also divisible by 6.


(b) 1258

Divisible by 2 because its units place is an even number but not divisible by 3 because the sum of its digits (= 16) is not divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.


(c) 4335

Not divisible by 2 because its units place is not an even number bit the given number is divisible by 3 because the sum of its digits (= 15) is divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.


(d) 61233

The given number is not divisible by 2 because its units place is not an even number but the given number is divisible by 3 because the sum of its digits (= 15) is divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.


(e) 901352

The given number is divisible by 2 because its units place is an even number but the given number is not divisible by 3 because the sum of its digits (= 20) is not divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.


(f) 438750

The given number is divisible by 2 because its units place is an even number but the given number is divisible by 3 because the sum of its digits (= 27) is not divisible by 3.

Since the number is divisible by both 2 and 3, therefore, it is divisible by 6.


(g) 1790184

The given number is divisible by 2 because its units place is an even number but the given number is divisible by 3 because the sum of its digits (= 30) is not divisible by 3.

Since the number is divisible by both 2 and 3, therefore, it is divisible by 6.


(h) 12583

The given number is not divisible by 2 because its units place is not an even number but the given number is not divisible by 3 because the sum of its digits (= 19) is not divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.



(i) 639210

The given number is divisible by 2 because its units place is an even number but the given number is divisible by 3 because the sum of its digits (= 21) is not divisible by 3.

Since the number is divisible by both 2 and 3, therefore, it is divisible by 6.


(j) 17852

The given number is divisible by 2 because its units place is an even number; the given number is not divisible by 3 because the sum of its digits (= 23) is not divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.



NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.3 with Answers

Question 4

Using divisibility test, determine which of the following numbers are divisible by 11:

(a) 5445 (b) 10824 (c) 7138965 (d) 70169308 (e) 10000001 (f) 901153


Answer 4

(a) 5445


Sum of the digits at odd places = 4 + 5 = 9

Sum of the digits at even places = 4 + 5 = 9

Difference of both sums = 9 – 9 = 0

Since the difference is 0, therefore, the number is divisible by 11.


(b) 10824

Sum of the digits at odd places = 4 + 8 +1 = 13

Sum of the digits at even places = 2 + 0 = 2

Difference of both sums = 13 – 2 = 11

Since the difference is 11, therefore, the number is divisible by 11.


(c) 7138965

Sum of the digits at odd places = 5 + 9 + 3 + 7 = 24

Sum of the digits at even places = 6 + 8 + 1 = 15

Difference of both sums = 24 – 15 = 9

Since the difference is neither 0 nor 11, therefore, the number is not divisible by 11.


(d) 70169308

Sum of the digits at odd places = 8 + 3 + 6 + 0 = 17

Sum of the digits at even places = 0 + 9 + 1 + 7 = 17

Difference of both sums = 17 – 17 = 0

Since the difference is 0, therefore, the number is divisible by 11.


(e) 10000001

Sum of the digits at odd places = 1 + 0 + 0 + 0 = 1

Sum of the digits at even places = 0 + 0 + 0 + 1 = 1

Difference of both sums = 1 – 1 = 0

Since the difference is 0, therefore, the number is divisible by 11.



(f) 901153

Sum of the digits at odd places = 3 + 1 + 0 = 4

Sum of the digits at even places = 5 + 1 + 9 = 15

Difference of both sums = 15 – 4 = 11

Since the difference is 11, therefore, the number is divisible by 11.




Question 5

Write the smallest digit and the largest digit in the blanks space of each of the following numbers so that the number formed is divisible by 3:

(a) __________ 6724 (b) 4765 __________ 2


Answer 5

(a) 6+7+2+4 =19

We know that a number is divisible by 3 if the sum of all digits is divisible by 3.

Therefore, Smallest digit : 2


26724 = 2 + 6 + 7 + 2 + 4 = 21


Largest digit Will be : 8

86724 = 8 + 6 + 7 + 2 + 4 = 27


(b)4+7+6+5+2=24

 We know that a number is divisible by 3 if the sum of all digits is divisible by 3.

Therefore, Smallest digit : 0

476502 = 4 + 7 + 6 + 5 + 0 + 2 = 24


Largest digit : 9

476592 = 4 + 7 + 6 + 5 + 9 + 2 = 33



Question 6

Write the smallest digit and the largest digit in the blanks space of each of the following numbers so that the number formed is divisible by 11:

(a) 92 __________ 389 (b) 8 __________ 9484


Answer 6: 

  1. sum of odd place disit: 9+8=17

sum of even place digits : 2+3+9=14

We know that a number is divisible by 11 if the difference of the sum of the digits 

at odd places and that of even places should be either 0 or 11.

Therefore the smallest or largest digit is 8

Therefore, the number is 928389


Odd places = 9 + 8 + 8 = 25

Even places = 2 + 3 + 9 = 14

Difference = 25 – 14 = 11


(b) sum of odd place disit:8+9+8=25

sum of even place digits :4+4=8

We know that a number is divisible by 11 if the difference of the sum of the digits 

at odd places and that of even places should be either 0 or 11.

Therefore the smallest or largest digit is 6

Therefore, the number is 869484


Odd places = 8 + 9 + 8 = 25

Even places = 6 + 4 + 4 = 14

Difference = 25 – 14 = 11



NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers Ex 3.3 with Answers

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